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CAHSEE Math: Algebra and Functions Drill 5, Problem 3. Solve the equation.
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CAHSEE Math 5.3 Number Sense 224 Views
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Description:
Number Sense Drill 5 Problem 3. Which of the following is equivalent to the expression?
Transcript
- 00:03
Here's a shmoop du jour for you and your... brain.
- 00:07
Which of the following is equivalent to 27 cubed times 3 over 243 squared?
- 00:15
And here are the potential answers...
- 00:21
OK, so what is this question testing?
- 00:23
Well, really it's testing how good we are at our multiplication tables, especially the
Full Transcript
- 00:27
column that deals with the number 3.
- 00:30
We could certainly brute force this question
- 00:31
and multiply 27 times 27 times 27.
- 00:35
We could also square 243.
- 00:37
But that won't scale for harder, bigger problems...
- 00:40
So let's try to do this the fancy, dancy... correct way...
- 00:44
and rewrite it as 3 cubed, which is 27.
- 00:47
Yep, 3 times 3 is 9... times 3 is 27 -- then cube the whole thing.
- 00:52
Then there's that 243 fella -- such a strange, random-looking number.
- 00:57
It should feel 'fishy' -- and if you were in the super advanced multiplication
- 01:01
tables group and played out that 3 times thing...
- 01:04
...you'd remember that 3 times 27 is 81... and 81 times 3 is -- yes -- ding ding ding.
- 01:10
So rewrite 243 as 3 to the 5th power.
- 01:14
Or rather, rewrite the whole problem now to look like this:
- 01:19
Now it's just about multiplying the exponents.
- 01:21
We get 3 to the 9th times the quantity 3 over 3 to the 10th.
- 01:26
Yet another curveball on this very gnarly problem -- remember that when multiplying
- 01:31
exponents, we can ADD the powers... AND remember that 3 is 3 to the FIRST power.
- 01:37
So we can rewrite the problem again as 3 to the 9th times 3 to the first... to get 3 to the 10th.
- 01:43
So what gives? We have 3 to the 10th over 3 to the 10th --
- 01:47
yeah -- a whole lotta work just to get... 1.
- 01:50
But at least we can get there by counting our fingers.
- 01:53
And... we're done. The answer is C.
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