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System Interactions and Changes Videos 15 videos

AP Physics 1: 1.1 System Interactions and Changes
196 Views

We wouldn't give away the answer to this AP Physics question, not for all the joules in the crown. Come back when you've got some actual jewels. Th...

AP Physics 1: 1.2 System Interactions and Changes
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AP Physics 1: 1.2 System Interactions and Changes. What is the total mechanical energy of the system?

AP Physics 1: 1.4 System Interactions and Changes
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AP Physics 1: 1.4 System Interactions and Changes. What is the change in linear momentum?

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AP Physics 1: 3.2 System Interactions and Changes 182 Views


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AP Physics 1: 3.2 System Interactions and Changes. Which of the following is closest to the cannonball's speed one second after launch?

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English Language

Transcript

00:00

Thank you We sneak and here's your shmoop du jour

00:05

brought to you by cannon balls They're capable of great

00:08

destructive force and are also our favorite way to enter

00:11

the swimming pool I checked the following diagram Alright a

00:15

cannonball with a mass of two hundred kilograms is ejected

00:19

from a cannon at t equals zero However the cannon

00:22

does not object with a constant force Instead it follows

00:25

the plot above using this information which of these speeds

00:29

is closest to that of the cannon ball One second

00:33

after the cannon is launched and the applied force goes

00:37

to zero All right And here the potential answer who

00:40

Good question Ah forced time graph We remember back when

00:45

we were young and saw forced time grab for the

00:47

first time It was new and scary Now that we're

00:50

old and withered We know how to make it work

00:52

for us right Well when we see this graph we

00:54

know we're dealing with impulse impulses The change in mo

00:57

mentum over an interval of time and mo mentum is

01:00

equal to mass times the change of velocity To find

01:05

the impulse using our force time graph we need to

01:07

figure out the area under the curve In our graph

01:10

here we could break it into two parts a triangle

01:13

and a rectangle Then we calculate the area of each

01:16

shape Well we'll tackle the triangle first To get that

01:18

we use the formula of one half base times height

01:21

Shmoop And then we'll take the area of the rectangle

01:27

base times height Well if we add them together we

01:33

get a total impulse of two thousand two hundred fifty

01:36

newton seconds All right because we now know the impulse

01:39

we can plug in our numbers and solve for velocity

01:42

right ankle Sometimes be i get to hand him over

01:46

to kilograms Let me point you alright so all we

01:50

have to do is around eleven point two five down

01:52

to eleven and will arrive at our answer option A 00:01:54.72 --> [endTime] That wasn't too bad We owe you

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