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System Interactions and Changes Videos 15 videos

AP Physics 1: 1.1 System Interactions and Changes
196 Views

We wouldn't give away the answer to this AP Physics question, not for all the joules in the crown. Come back when you've got some actual jewels. Th...

AP Physics 1: 1.2 System Interactions and Changes
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AP Physics 1: 1.2 System Interactions and Changes. What is the total mechanical energy of the system?

AP Physics 1: 1.4 System Interactions and Changes
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AP Physics 1: 1.4 System Interactions and Changes. What is the change in linear momentum?

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AP Physics 1: 3.1 System Interactions and Changes 198 Views


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AP Physics 1: 3.1 System Interactions and Changes. What is the coefficient of friction between the biscuit and the court?

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English Language

Transcript

00:00

Thank you We sneak and here's your shmoop too sure

00:05

brought to you by shuffleboard it's fun to play and

00:08

equally fun when older people call us the w word

00:12

whipper snapper all right shuffle boards a sport typically played

00:16

by retirees on cruise ships Grandpa shmoop stands at one

00:19

end of a narrow lane A grid with various scores

00:22

is located at the other end He uses a broom

00:25

to push a pot called a biscuit down the lane

00:28

If grandpa shmoop gives the four kilogram biscuit an initial

00:31

speed of five meters per second and the biscuit comes

00:35

to rest after ten meters what is the coefficient of

00:38

friction between the biscuit and the court And here the

00:41

potential answers All right well this could get complicated if

00:47

we let it The biscuit starts off with kinetic energy

00:51

and kinetic energy equals one half mass times velocity square

00:56

The coefficient of friction then goes to work on the

00:59

puck taking that kinetic energy away Well looks like this

01:03

is a job for the work energy the're Um the

01:06

work energy tour means that the work done by a

01:08

force becomes the kinetic energy of the object of forces

01:12

working on here's The equation In this case the biscuit

01:15

is losing energy so the changing kinetic energy is negative

01:20

and the work is negative as well So in our

01:25

question here the work done by friction is equal to

01:28

the change in kinetic energy Equation For the force of

01:31

kinetic friction is mass times gravity times that coefficient And

01:36

since we're working here we have to include displacement represented

01:40

by x Well now we can solve for the coefficient

01:43

you and we can see that as we solve this

01:46

equation we don't actually use the objects mass It cancels

01:49

itself out Coefficient mu equals velocity squared divided by two

01:55

tons Gravity times displacement So when we plug in those

01:59

numbers we get an answer of one eighth So option 00:02:02.49 --> [endTime] a Yeah that's it that's the correct answer

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