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ACT Math: Plane Geometry Drill 3, Problem 1. What is the area of the trapezoid shape in the video?
ACT Math Intermediate Algebra Drill 1, Problem 1. What is the product of (a – 3)2?
ACT Math Intermediate Algebra Drill 1, Problem 4. Solve for x based on the equation.
ACT Math 3.4 Elementary Algebra 235 Views
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Description:
ACT Math Elementary Algebra Drill 3, Problem 4. Solve for y in this equation.
- Elementary Algebra / Solving simple quadratic equations
- Product Type / ACT Math
- Foreign Language / Arabic Subtitled
- Foreign Language / Korean Subtitled
- Foreign Language / Chinese Subtitled
- Foreign Language / Spanish Subtitled
- Algebra / Understand the relationship between zeros and factors of polynomials
- Algebra / Understand the relationship between zeros and factors of polynomials
- Algebra / Use polynomial identities to solve problem
- Algebra / Understand the relationship between zeros and factors of polynomials
- Algebra / Use polynomial identities to solve problems
- Elementary Algebra / Solve quadratic equations by factoring
Transcript
- 00:02
For a good time, solve this shmoopy question... Solve for y: 2y squared plus 7y plus 3 equals 0
- 00:10
And here are the potential answers...
- 00:15
Ok. It's just a basic factoring question. It's in the form of something squared plus something
- 00:20
plus an integer equals zero.
- 00:22
A bell should be going off when we see an equation like this.
Full Transcript
- 00:25
We just have to figure out what the factors are... and there's a bit of a curveball in
- 00:29
here in that there's a 2 on the front end.
- 00:32
So we know that one of the factors is going to be a 2, as in:
- 00:35
The quantity 2y plus something times the quantity y plus something.
- 00:38
Let's plug in some numbers to get the 3. It's kind of easy because 3 only has 2 factors:
- 00:44
1 and 3...
- 00:46
Now we have quantity 2y plus 1 times quantity y plus 3.
- 00:50
If we multiply it out, we get 2y times y here, which is 2y squared.
- 00:55
Then we have 2y times 3, which is 6y
- 00:57
plus y times 1, which is just... y.
- 01:01
6y plus y is 7y; then, 1 times 3 is just 3 so we're done.
- 01:07
But now... how do we make the whole thing equal to zero? Well, one of the elements here
- 01:11
has to BE zero.
- 01:14
If y is negative 3 then this one is 3 minus 3 which is 0...
- 01:20
...and here, it's just negative one half, because negative 1 half times 2 is negative
- 01:24
1... and negative 1 plus positive 1 is zero.
- 01:27
So the other answer is negative one half and the answer is A and C...
- 01:31
...or option E.
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