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SAT Math 9.2 Algebra and Functions 377 Views
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Description:
SAT Math 9.2 Algebra and Functions
Transcript
- 00:02
Put this in your calculator and shmoop it.
- 00:05
If the square root of 25 minus x squared equals 3, then what is one possible positive value of x?
- 00:15
So we want to find this “x” fellow. In other words… we want to isolate it.
- 00:20
The side of the equation that contains x is under a square root.
- 00:23
We can undo this situation by squaring both sides, getting us 25 – x squared = 9.
Full Transcript
- 00:31
Then, we subtract 25 from each side to further isolate x. Now we’re working with –x squared = -16.
- 00:40
Both sides are negative, so we can multiply both sides by -1 to get x squared = 16.
- 00:46
From here, pretty simple. Take the square root of both sides, and we get 4.
- 00:50
But don’t forget it can be positive OR negative.
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