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CAHSEE Algebra I: Drill 1, Problem 1. What are some of the properties used to solve this equation?
CAHSEE Math Algebra I: Drill 1, Problem 2. Find the negative reciprocal.
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Description:
CAHSEE Math Algebra I: Drill 6, Problem 4. How much more ground can the Batmobile cover traveling at a speed of 75 mph in the same amount of time?
Transcript
- 00:03
Here’s a shmoopy question for ya…
- 00:05
Batman totally forgot he was supposed to be back in Gotham for a… business meeting in about an hour.
- 00:10
The Batmobile, traveling at an average of 60 mph, took a certain amount of time to cover
- 00:15
a distance of 80 miles.
- 00:17
How much more ground can it cover traveling at a speed of 75 mph in the same amount of time?
Full Transcript
- 00:23
Here are the potential answers…
- 00:28
So… what is this question asking?
- 00:30
It’s a distance, rate and time problem which we have to just think through.
- 00:34
First, let’s put everything in the same units.
- 00:37
In this problem, we’re all miles… Batman wouldn’t dare fool around with kilometers.
- 00:41
That’s Alfred’s thing.
- 00:43
The Batmobile was going 60 miles an hour, so it can travel, well… 60 miles
- 00:47
in one hour… or 1 mile per minute.
- 00:49
So if it goes 80 miles, then it’s travelled 80 minutes.
- 00:53
But the key thing to glean here is that the Batmobile went for 80 minutes… or an hour
- 00:57
and 20 minutes… or 1.33 hours.
- 01:02
So now what if the Batmobile didn’t hit much traffic and was instead going 75 miles an hour?
- 01:07
To figure out how far it would have driven in that same amount of time, we multiply its
- 01:11
rate of 75 mph by 1.33 and we get… about 100 miles.
- 01:16
So the DIFFERENCE between the two distances is 20 miles.
- 01:22
Answer A. As in, "Alfred."
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