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Algebra and Functions Videos 33 videos
Algebra and Functions: Drill Set 6, Problem 1. Solve the inequality.
Algebra and Functions: Drill Set 6, Problem 2. Solve the inequality.
CAHSEE Math Algebra and Functions: Drill Set 1, Problem 4. Which operation should be performed first?
CAHSEE Math 1.1 Algebra and Functions 291 Views
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Description:
CAHSEE Math Algebra and Functions: Drill Set 1, Problem 1. At this rate, what is the total cost of 10 songs?
- Functions / Build a function that model a relationship between two quantities
- Functions / Build functions that model a relationship between two quantities
- Functions / Build a function that models a relationship between two quantities
- Functions / Build a function that models a relationship between two quantities
- Algebra and Functions / Rate, speed, distance, and time
Transcript
- 00:03
Here's a shmoopy question for you...
- 00:07
Unlike his shady friend Dishonest Paul, Honest John actually pays for songs from iTunes.
- 00:13
He pays for x number of songs at a total cost of $12.50.
- 00:19
At this rate, what is the total cost of 10 songs?
- 00:22
Here are the potential answers...
Full Transcript
- 00:24
Alright, hit pause. Try it yourself.
- 00:29
OK, this question is testing whether we know the business formula for cost...
- 00:34
...or a fancy way of asking us to calculate the unit price times a quantity.
- 00:39
The formula looks like this:
- 00:40
Price times quantity equals total cost.
- 00:44
Well, we know the base elements here...
- 00:46
Price times number of songs equals $12.50.
- 00:49
So we can set up the equation... px equals 12.5
- 00:54
We should isolate p in the equation because we'll want to use p later to find the total
- 00:58
cost of 10 songs...or 10p.
- 01:01
To isolate p, we can divide x from both sides of the equation... getting p equals 12.5 over x.
- 01:08
Remembering that we want to find 10p...
- 01:10
we can multiply 10 times 12.5 over x to get 125 over x.
- 01:16
And it looks like our answer is B.
- 01:19
Of course, if your name is Dishonest Paul, you already knew that.
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